LINQ_List_Any_Cast1.htm |
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Code : LINQ_List_Any_Cast1.txt |
Enumerable Method: Distinct:
- Adding data to an Array List
List<ObjectFacotry> listempdb = of1.cEmp();
ArrayList ar1 = new ArrayList();
foreach (var v1 in listempdb)
{
ar1.Add(v1.ename + " " + v1.job + " \t" + v1.deptno);
}
- IEnumerable<string> query =
ar1.Cast<string>().Distinct().Select(e1 => e1);
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Note with out distinct, "Miller CLERK 10", displayed twice due to a
redundant row in the data source
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